r - How can i rapidly explore the classes of all columns in a dataframe? -

-

i want rapidly explore classes of columns in dataframe, made function print columns names , arrange them class. want tell me numbers of columns aren't of class factor.

columnsclass<-function (x){ a<-vector() b<-vector(mode="character") c<-vector c=0 (i in 1:dim(x)[2]){ a[i]<-paste(class(x[,i]),names(x)[i],sep="--") if (class(x[,i])!= "factor"){ c<-c+1 b[c]<<-i }} #1st print print(sort(a)) #2nd print print(paste("columns aren't factors number:",paste(b,collapse=","),collapse="  "))     }

however when run it, doesn't #2nd print though code working.

> columnsclass(cars)  [1] "numeric--dist"  "numeric--speed" [1] "columns aren't factors number: " #it doesn't print numbers of columns of class factor if run separately ,it  runs > print(paste("columns aren't factors   number:",paste(b,collapse=","),collapse="  ")) [1] "columns aren't factors number: 1,2"

here's function takes account pierre's comments, simplifies a's calculation well:

columnsclass <- function(x){   nm <- sapply(x, class)   <- paste(nm, names(nm), sep = "--")   b <- which(!sapply(x, is.factor))   # 1st print   print(sort(a))   # 2nd print   print(paste("columns aren't factors number:",      paste(b, collapse = ","), collapse = "  "))     } > columnsclass(cars) [1] "numeric--dist"  "numeric--speed" [1] "columns aren't factors number: 1,2"

Comments

Post a Comment

Popular posts from this blog

ruby - Trying to change last to "x"s to 23 -

-
i have been playing around irb , have string looks this: irb(main):072:0> puts ["[\"4354 5432 5432 xxxxx\", \"6547 6547 8543 xxxxx\", \"2344 6543 6674 xxxxx\", \"2346 6236 7543 xxxxx\", \"1273 5585 5587 xxxxx\"]"] => nil irb(main):073:0> what want gsub last 2 "x" s of each 17 digit combination, 23 . what i've tried far (i've been using rubular): a.gsub(/\d[x]/,"23") <= grabs "x" s i'm close a.gsub(/\w[x{2}]/,"23") <= grabs "x" s grabs two digits each combination. is there easier way i'm not understanding? a.gsub(/\d{4} \d{4} \d{4} xxx\kxx/, '23') \d{4} = 4 digits what \k drop matched far. can use don't replace entire number, still able validate have in desired format.
Read more

jquery - Clone last and append item to closest class -

-
this bare-bones code on page: <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <di...
Read more

css - Can I use the :after pseudo-element on an input field? -

-
i trying use :after css pseudo-element on input field, not work. if use span , works ok. <style type="text/css"> .mystyle:after {content:url(smiley.gif);} .mystyle {color:red;} </style> this works (puts smiley after "buu!" , before "some more") <span class="mystyle">buuu!</span>a more this not work - colors somevalue in red, there no smiley. <input class="mystyle" type="text" value="somevalue"> what doing wrong? should use pseudo-selector? note: cannot add span around input , because being generated third-party control. :after , :before not supported in internet explorer 7 , under, on elements. it's not meant used on replaced elements such form elements (inputs) , image elements . in other words it's impossible pure css. however if using jquery can use $(".mystyle").after("add smiley here"); api docs on .after to ...
Read more