python - Using openpyxl to copy from one workbook to another results in error when saving -

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i trying append values 1 sheet row row new workbook. code works when run on small test file, when run on target file returns error when saving.

here code:

from openpyxl import load_workbook openpyxl import workbook  wb = load_workbook(filename='rm activity-pricing report - 2014-05-31.xlsm',keep_vba=false, data_only=true) ws_ottawa = wb.get_sheet_by_name('ottawa')  wb2 = workbook() ws2 = wb2.create_sheet()  row in ws_ottawa.iter_rows():         ws2.append(row)  wb2.save('new_big_file.xlsx')

the output error in spyder (python 3.5) is:

traceback (most recent call last):  file "<ipython-input-22-171ffbcd4891>", line 1, in <module> runfile('z:/revenue management report/extractpromodata.py', wdir='z:/revenue management report')  file "c:\anaconda3-64\lib\site-packages\spyderlib\widgets\externalshell\sitecustomize.py", line 699, in runfile execfile(filename, namespace)  file "c:\anaconda3-64\lib\site-packages\spyderlib\widgets\externalshell\sitecustomize.py", line 88, in execfile exec(compile(open(filename, 'rb').read(), filename, 'exec'), namespace)  file "z:/revenue management report/extractpromodata.py", line 35, in <module> wb2.save('new_big_file4.xlsx')  file "c:\anaconda3-64\lib\site-packages\openpyxl\workbook\workbook.py", line 298, in save save_workbook(self, filename)  file "c:\anaconda3-64\lib\site-packages\openpyxl\writer\excel.py", line 198, in save_workbook writer.save(filename, as_template=as_template)  file "c:\anaconda3-64\lib\site-packages\openpyxl\writer\excel.py", line 181, in save self.write_data(archive, as_template=as_template)  file "c:\anaconda3-64\lib\site-packages\openpyxl\writer\excel.py", line 87, in write_data self._write_worksheets(archive)  file "c:\anaconda3-64\lib\site-packages\openpyxl\writer\excel.py", line 114, in _write_worksheets write_worksheet(sheet, self.workbook.shared_strings,  file "c:\anaconda3-64\lib\site-packages\openpyxl\writer\worksheet.py", line 233, in write_worksheet write_rows(xf, worksheet)  file "c:\anaconda3-64\lib\site-packages\openpyxl\writer\lxml_worksheet.py", line 59, in write_rows if cell.value none , not cell.has_style:  file "c:\anaconda3-64\lib\site-packages\openpyxl\cell\cell.py", line 306, in value if value not none , self.is_date:  file "c:\anaconda3-64\lib\site-packages\openpyxl\cell\cell.py", line 351, in is_date if self.data_type == "n" , self.number_format != "general":  file "c:\anaconda3-64\lib\site-packages\openpyxl\styles\styleable.py", line 49, in __get__ return coll[idx - 164] indexerror: list index out of range

i not error when use code on smaller test .xlsx file.

possible reasons problem suspect are:

1)input file .xlsm

2)input file has columns ci

3)input file password protected (but since error in saving not seem should issue)

taking account charlie said, work-around openpyxl import load_workbook openpyxl import workbook

 wb = load_workbook(filename='rm activity-pricing report - 2014-5-31.xlsm',keep_vba=false, data_only=true)#,guess_types=true)   ws_ottawa = wb.get_sheet_by_name('ottawa')  wb2 = workbook() ws2 = wb2.create_sheet() counter = 0 new_rows = [] rrow in ws_ottawa.iter_rows():     new_rows.append([])     cell in rrow:         new_rows[counter].append(cell.value)     counter +=1 wrow in new_rows:      ws2.append(wrow)  wb2.save('new_big_file4.xlsx')   print("all done")

you quite cannot trying do. unfortunately, way data stored within file formats means relevant information not stored cell using reference workbook object. these differ workbook workbook why see errors when saving: number format want use doesn't exist in new file.


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