angularjs - How to send binary data to API with Angular js -

-

i trying send image binary api.

the api has mode can send url, if code works fine. want send binary image html canvas. here's docs of api can see parameter https://dev.havenondemand.com/apis/ocrdocument#request

i error alert when call getocr method. leads me think api call isnt being made correctly. pls help.

here's send function looks like.

$scope.getocr = function(imagedata){     var apikey = 'xxxxxx';     var requeststring = 'https://api.havenondemand.com/1/api/sync/ocrdocument/v1?apikey='+ apikey +'&file='+ "data:image/jpeg;base64," + imagedata;      $http.get(requeststring).then(function(resp) {         alert(angular.fromjson(resp.data).text_block[0]['text']);         }, function(err) {             alert('error');           }) }

and here's looks when call method

$cordovacamera.getpicture(options).then(function(imagedata) {         $scope.imguri = "data:image/jpeg;base64," + imagedata;          $scope.getocr(imagedata);      },     function(err) {         // error occured. show message user     });

well, first off, looks you're adding data:image/jpeg;base64 prefix twice. once in getpicture(options).then(), when construct request url. use browser dev tools inspect request , verify it's expect.

edit: looks api may expecting post request image data multipart form data? not entirely sure, documentation doesn't seem complete.


Comments

Post a Comment

Popular posts from this blog

ruby - Trying to change last to "x"s to 23 -

-
i have been playing around irb , have string looks this: irb(main):072:0> puts ["[\"4354 5432 5432 xxxxx\", \"6547 6547 8543 xxxxx\", \"2344 6543 6674 xxxxx\", \"2346 6236 7543 xxxxx\", \"1273 5585 5587 xxxxx\"]"] => nil irb(main):073:0> what want gsub last 2 "x" s of each 17 digit combination, 23 . what i've tried far (i've been using rubular): a.gsub(/\d[x]/,"23") <= grabs "x" s i'm close a.gsub(/\w[x{2}]/,"23") <= grabs "x" s grabs two digits each combination. is there easier way i'm not understanding? a.gsub(/\d{4} \d{4} \d{4} xxx\kxx/, '23') \d{4} = 4 digits what \k drop matched far. can use don't replace entire number, still able validate have in desired format.
Read more

jquery - Clone last and append item to closest class -

-
this bare-bones code on page: <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <di...
Read more

css - Can I use the :after pseudo-element on an input field? -

-
i trying use :after css pseudo-element on input field, not work. if use span , works ok. <style type="text/css"> .mystyle:after {content:url(smiley.gif);} .mystyle {color:red;} </style> this works (puts smiley after "buu!" , before "some more") <span class="mystyle">buuu!</span>a more this not work - colors somevalue in red, there no smiley. <input class="mystyle" type="text" value="somevalue"> what doing wrong? should use pseudo-selector? note: cannot add span around input , because being generated third-party control. :after , :before not supported in internet explorer 7 , under, on elements. it's not meant used on replaced elements such form elements (inputs) , image elements . in other words it's impossible pure css. however if using jquery can use $(".mystyle").after("add smiley here"); api docs on .after to ...
Read more