How to forward TCP/UDP ports in Debian 7 (64BIT)? -

-

i have friend using ovh vps (debian 7, 64 bits) , want open tcp , udp ports dont know why. try access got timed_out, think firewall blocking connection. tried on different computers same issue. vps firewall? please command forward ports or add firewall exception in debian 7. thanks.

welcome wonderful world of iptables
information interested in surrounds iptables package, default firewall logic number of linux distributions.

to answer question simply, following should permit traffic through port 80 "anywhere", example. modify see fit, , see basic port opening requirements met.

sudo iptables -a input -p tcp --dport 80 -j accept

similarly, if needed open udp port 9987 (default teamspeak), command this.

sudo iptables -a input -p udp --dport 9987 -j accept

lastly, iptables configuration commands saved in memory. "commit" changes persist reboot, must save them.

sudo service iptables save

here additional trustworthy resources on iptables educational pleasure.

  1. https://wiki.debian.org/iptables
  2. http://ubuntuforums.org/showthread.php?t=159661
  3. https://wiki.centos.org/howtos/network/iptables

Comments

Post a Comment

Popular posts from this blog

ruby - Trying to change last to "x"s to 23 -

-
i have been playing around irb , have string looks this: irb(main):072:0> puts ["[\"4354 5432 5432 xxxxx\", \"6547 6547 8543 xxxxx\", \"2344 6543 6674 xxxxx\", \"2346 6236 7543 xxxxx\", \"1273 5585 5587 xxxxx\"]"] => nil irb(main):073:0> what want gsub last 2 "x" s of each 17 digit combination, 23 . what i've tried far (i've been using rubular): a.gsub(/\d[x]/,"23") <= grabs "x" s i'm close a.gsub(/\w[x{2}]/,"23") <= grabs "x" s grabs two digits each combination. is there easier way i'm not understanding? a.gsub(/\d{4} \d{4} \d{4} xxx\kxx/, '23') \d{4} = 4 digits what \k drop matched far. can use don't replace entire number, still able validate have in desired format.
Read more

jquery - Clone last and append item to closest class -

-
this bare-bones code on page: <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <di...
Read more

css - Can I use the :after pseudo-element on an input field? -

-
i trying use :after css pseudo-element on input field, not work. if use span , works ok. <style type="text/css"> .mystyle:after {content:url(smiley.gif);} .mystyle {color:red;} </style> this works (puts smiley after "buu!" , before "some more") <span class="mystyle">buuu!</span>a more this not work - colors somevalue in red, there no smiley. <input class="mystyle" type="text" value="somevalue"> what doing wrong? should use pseudo-selector? note: cannot add span around input , because being generated third-party control. :after , :before not supported in internet explorer 7 , under, on elements. it's not meant used on replaced elements such form elements (inputs) , image elements . in other words it's impossible pure css. however if using jquery can use $(".mystyle").after("add smiley here"); api docs on .after to ...
Read more