php - view table joins in codeigniter -

-

i have 2 tables category table , factory table. in category table have following rows.

idcategory category

in factory table have following rows.

idfactories factoryname postcode country telephone number email website profile adress idcategory

i have table have idfactory , idcategory stored too.

my factorycategories table has following rows.

idfactorycat idfactory idcategory factorycat

i made join in category model because want categories on site , when click on category factories stored in category has show up.

in model have

$this->db->select('*'); $this->db->from('bedrijfcategorieen'); $this->db->join('bedrijfcategorieen', 'bedrijfcategorieen.idbedrijven = bedrijven.idbedrijven'); $this->db->join('bedrijfcategorieen', 'bedrijfcategorieen.idcategorieen = categorieen.idcategorieen'); $query = $this->db->get();

what have store in controller , views? new codeigniter.

ps: translated rows easy understand others because dutch.

thanks

edit: it's bit tricky explain have sidebar catogories.

categories  cars cars parts books etc etc...

i want create links each category.

when click on, let's cars. want go results page factories showed have category id=1 because cars has id=1. actual question. , think need join that.

hope understand it.

thanks again.

edit match edit

based on edit, i'm giving basic ideas here. please refer codeigniter manual details:

//model

function getresults($segment3){     $this->db->select('*');     $this->db->from('category');     $this->db->join('factories', 'category.idcategory. ' = factories.idfactories');     $this->db->join('factorycategories', 'factorycategories.idfactory = ' . $segment3);       $query = $this->db->get();     return $query->result(); }  //note return results match in tables.  //if need return more of table, use right join or left join.   function categories(){ //call controller create initial links     $query = $this->db->get('category');     return $query->result(); }

//controller

function pagecategories(){ // shows initial categories links on page     $data["links"] = $this->modelname->categories();     $this->load->view("page-to-view"); }  function pagefactories(){ // takes categories , shows factories     $this->load->helper('url');     $segment3 = $this->uri->segment(3);     $data["results"] = $this->modelname->getresults($segment3);       $this->load->view("page-to-view"); }

//view

print_r($results); //run test - debug

show links (note segment pattern):

if(isset($links) && is_array($links)){     foreach($links $k => $value){         echo '<a href="'.base_url().'yourcontroller/pagefactories/'.$value->idcategory.' ">' .$value->category. '</a>';         echo "<br />";     } }  if(isset($results ) && is_array($results )){     foreach($results $key => $row){         echo $row->category;         echo "<br />";         echo $row->factoryname;         //it goes on as want     } }

this big picture.

how you'd convert dutch can't figure out. note: google.translate.com mess lots of white spaces might have clean up.


Comments

Post a Comment

Popular posts from this blog

ruby - Trying to change last to "x"s to 23 -

-
i have been playing around irb , have string looks this: irb(main):072:0> puts ["[\"4354 5432 5432 xxxxx\", \"6547 6547 8543 xxxxx\", \"2344 6543 6674 xxxxx\", \"2346 6236 7543 xxxxx\", \"1273 5585 5587 xxxxx\"]"] => nil irb(main):073:0> what want gsub last 2 "x" s of each 17 digit combination, 23 . what i've tried far (i've been using rubular): a.gsub(/\d[x]/,"23") <= grabs "x" s i'm close a.gsub(/\w[x{2}]/,"23") <= grabs "x" s grabs two digits each combination. is there easier way i'm not understanding? a.gsub(/\d{4} \d{4} \d{4} xxx\kxx/, '23') \d{4} = 4 digits what \k drop matched far. can use don't replace entire number, still able validate have in desired format.
Read more

jquery - Clone last and append item to closest class -

-
this bare-bones code on page: <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <di...
Read more

css - Can I use the :after pseudo-element on an input field? -

-
i trying use :after css pseudo-element on input field, not work. if use span , works ok. <style type="text/css"> .mystyle:after {content:url(smiley.gif);} .mystyle {color:red;} </style> this works (puts smiley after "buu!" , before "some more") <span class="mystyle">buuu!</span>a more this not work - colors somevalue in red, there no smiley. <input class="mystyle" type="text" value="somevalue"> what doing wrong? should use pseudo-selector? note: cannot add span around input , because being generated third-party control. :after , :before not supported in internet explorer 7 , under, on elements. it's not meant used on replaced elements such form elements (inputs) , image elements . in other words it's impossible pure css. however if using jquery can use $(".mystyle").after("add smiley here"); api docs on .after to ...
Read more