bash - How can I rename of old files? -

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i have directory this:

-rw-r--r--  1 root root    0 jan  7 15:04 tmp_file2015_123_1_3123.log -rw-r--r--  1 root root    0 jan  7 15:04 tmp_file2015_133_1_3123.log -rw-r--r--  1 root root    0 jan  7 16:04 tmp_file2015_133_1_3125.log -rw-r--r--  1 root root    0 jan  7 16:04 tmp_file2015_133_1__3223125.log -rw-r--r--  1 root root    0 jan  7 16:04 tmp_file2015_133_1_3223125.log

i need remove tmp_ , can this:

for in *; s=$(sed -r 's/^(tmp_)(.*.log)/\2/' <<< $i); if [[ "$i" != "$s" ]]; mv "$i" "$s"; fi; done;

but need older 1 hour (modified time) files:

for example ( now: jan 7 16:10 ):

-rw-r--r--  1 root root    0 jan  7 13:00 file2015_123_1_3123.log -rw-r--r--  1 root root    0 jan  7 15:04 file2015_133_1_3123.log -rw-r--r--  1 root root    0 jan  7 15:01 file2015_133_1_3125.log -rw-r--r--  1 root root    0 jan  7 16:04 tmp_file2015_133_1__3223125.log -rw-r--r--  1 root root    0 jan  7 16:10 tmp_file2015_133_1_3223125.log

how can that?

this operate on files modified in last hour:

for orig_file in $(find . -type f -depth 1 -mtime -60m);     new_file="${orig_file#./tmp_}"     if [[ "$new_file" != "$orig_file" ]];         mv "$orig_file" "$new_file";     fi; done

if want operate on files older 1 hour use +60m instead

i've changed use of sed use built in bash functionality.


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