java - Android SimpleDateFormat returning incorrect time between midnight and 1am -

-

solved have found between midnight , 1am device returns time 1 hour later (the other 23 hours day returns correctly). more weirdly returns correctly if use kk instead of hh (though resulting string no use me)

code running: (in instance strformat matches hardcoded string in df3)

simpledateformat df = new simpledateformat(strformat, locale.us); simpledateformat df2 = new simpledateformat("yyyy-mm-dd kk:mm", locale.us); simpledateformat df3 = new simpledateformat("yyyy-mm-dd hh:mm:ss.sss", locale.us);  date d = c.gettime(); string s = d.tostring(); string ret = df.format(c.gettime()); string ret2 = df.format(new date(system.currenttimemillis())); string ret3 = df2.format(c.gettime()); string ret4 = df3.format(c.gettime()); string r1 = ""+c.get(calendar.hour);

these return:

s = "thu jan 07 00:39:32 gmt-11:00 2016" ret = "2016-01-07 01:39:32" ret2 = "2016-01-07 01:39:32" ret3 = "2016-01-07 24:39" ret4 = "2016-01-07 01:39:32.525" r1 = "0"

after 1am these return:

s = "thu jan 07 01:07:09 gmt-11:00 2016" ret = "2016-01-07 01:07:09" ret2 = "2016-01-07 01:07:09" ret3 = "2016-01-07 01:07" ret4 = "2016-01-07 01:07:09.606" r1 = "1"

any in have done wrong/what going wrong appreciated.

update

changing code to:

simpledateformat df = new simpledateformat(strformat, locale.us);         df.settimezone(timezone.gettimezone("gmt"));         simpledateformat df2 = new simpledateformat("yyyy-mm-dd kk:mm zzz", locale.us);         df2.settimezone(timezone.gettimezone("gmt"));         simpledateformat df3 = new simpledateformat("yyyy-mm-dd hh:mm:ss.sss zzz", locale.us);         df3.settimezone(timezone.gettimezone("gmt"));         date d = c.gettime();         string s = d.tostring();         string ret = df.format(c.gettime());         string ret2 = df.format(new date(system.currenttimemillis()));         string ret3 = df2.format(c.gettime());         string ret4 = df3.format(c.gettime());         string r1 = ""+c.get(calendar.hour);         return ret;

i same results:

s = "fri jan 08 00:52:05 gmt 2016" ret = "2016-01-08 01:52:05" ret2 = "2016-01-08 01:52:05" ret3 = "2016-01-08 24:52 gmt" ret4 = "2016-01-08 01:52:05.169 gmt" r1 = "0"

and

s = "fri jan 08 01:03:23 gmt 2016" ret = "2016-01-08 01:03:23" ret2 = "2016-01-08 01:03:23" ret3 = "2016-01-08 01:03 gmt" ret4 = "2016-01-08 01:03:23.547 gmt" r1 = "1"

so problem seems unrelated timezone

may have set timezone dateformat objects.

i tried : 

    calendar c = new gregoriancalendar(timezone.gettimezone("gmt-11:00"), locale.us);     c.set(2016, 0, 7, 00, 39, 32);     date date  = c.gettime();      simpledateformat df = new simpledateformat("eee mmm dd hh:mm:ss zzz yyyy", locale.us);     df.settimezone(timezone.gettimezone("gmt-11:00"));     simpledateformat df2 = new simpledateformat("yyyy-mm-dd kk:mm", locale.us);     df2.settimezone(timezone.gettimezone("gmt-11:00"));     simpledateformat df3 = new simpledateformat("yyyy-mm-dd hh:mm:ss.sss", locale.us);     df3.settimezone(timezone.gettimezone("gmt-11:00"));      string ret = df.format(date.gettime());     string ret2 = df.format(date.gettime());     string ret3 = df2.format(date.gettime());     string ret4 = df3.format(date.gettime());      system.out.println("  ret : "+ret);     system.out.println("  ret2 : "+ret2);     system.out.println("  ret3 kk: "+ret3);     system.out.println("  ret4 : "+ret4);

the result correct :

 ret : thu jan 07 00:39:32 gmt-11:00 2016  ret2 : thu jan 07 00:39:32 gmt-11:00 2016  ret3 kk: 2016-01-07 24:39  ret4 : 2016-01-07 00:39:32.217

Comments

Post a Comment

Popular posts from this blog

ruby - Trying to change last to "x"s to 23 -

-
i have been playing around irb , have string looks this: irb(main):072:0> puts ["[\"4354 5432 5432 xxxxx\", \"6547 6547 8543 xxxxx\", \"2344 6543 6674 xxxxx\", \"2346 6236 7543 xxxxx\", \"1273 5585 5587 xxxxx\"]"] => nil irb(main):073:0> what want gsub last 2 "x" s of each 17 digit combination, 23 . what i've tried far (i've been using rubular): a.gsub(/\d[x]/,"23") <= grabs "x" s i'm close a.gsub(/\w[x{2}]/,"23") <= grabs "x" s grabs two digits each combination. is there easier way i'm not understanding? a.gsub(/\d{4} \d{4} \d{4} xxx\kxx/, '23') \d{4} = 4 digits what \k drop matched far. can use don't replace entire number, still able validate have in desired format.
Read more

jquery - Clone last and append item to closest class -

-
this bare-bones code on page: <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <di...
Read more

css - Can I use the :after pseudo-element on an input field? -

-
i trying use :after css pseudo-element on input field, not work. if use span , works ok. <style type="text/css"> .mystyle:after {content:url(smiley.gif);} .mystyle {color:red;} </style> this works (puts smiley after "buu!" , before "some more") <span class="mystyle">buuu!</span>a more this not work - colors somevalue in red, there no smiley. <input class="mystyle" type="text" value="somevalue"> what doing wrong? should use pseudo-selector? note: cannot add span around input , because being generated third-party control. :after , :before not supported in internet explorer 7 , under, on elements. it's not meant used on replaced elements such form elements (inputs) , image elements . in other words it's impossible pure css. however if using jquery can use $(".mystyle").after("add smiley here"); api docs on .after to ...
Read more