javascript - D3.js Multiple Line Chart -

-

i tried show 2 line chart using d3.js,

i can display first chart "blob",

but doesn't work "blub"!!

how can fix , how simplify loop?

var canvas=d3.select("body")  	.append("svg")  	.attr("width",500).attr("height",300);    var donnees= {      blob:[        {x:10,y:20},{x:20,y:60}, {x:30,y:70},        {x:40,y:202},{x:50,y:260}, {x:60,y:70},        {x:70,y:75},{x:80,y:70}, {x:90,y:0}      ],      blub:[        {x:100,y:20},{x:110,y:20},{x:120,y:60}, {x:130,y:70},        {x:140,y:32},{x:150,y:60}, {x:160,y:90},        {x:170,y:75},{x:180,y:100}, {x:190,y:20}      ]  };      var groupe= canvas.append("g")      .attr("transform", "translate(20,20)");  var line= d3.svg.line()      .x (function(d){return d.x})      .y (function(d){return d.y});  var colors = d3.scale.category20();    var index = 0;  (var in donnees) {  	groupe.selectall("path")      .data([donnees[i]])      .enter()      .append("path")      .attr("d",line)      .attr("fill", "none")      .attr("stroke", colors(index))      .attr("stroke-width","1");    index++  }
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js"></script>

first off, don't need loop here (you never in d3), can use nested selections:

groupe.selectall("g")   .data(d3.values(donnees))   .enter()   .append("g")   .selectall("path")   .data(function(d) { return [d]; })   .enter()   .append("path")   ...

the problem you're seeing because you're selecting path elements, which, after first iteration of loop, there already. is, data provide in .data() matched existing path element , hence .enter() selection empty, adding nothing. can work around e.g. assigning class each path allows distinguish them, better solution use nested selection i've outlined above.

complete demo here.

see this tutorial more details on how selections work.


Comments

Post a Comment

Popular posts from this blog

ruby - Trying to change last to "x"s to 23 -

-
i have been playing around irb , have string looks this: irb(main):072:0> puts ["[\"4354 5432 5432 xxxxx\", \"6547 6547 8543 xxxxx\", \"2344 6543 6674 xxxxx\", \"2346 6236 7543 xxxxx\", \"1273 5585 5587 xxxxx\"]"] => nil irb(main):073:0> what want gsub last 2 "x" s of each 17 digit combination, 23 . what i've tried far (i've been using rubular): a.gsub(/\d[x]/,"23") <= grabs "x" s i'm close a.gsub(/\w[x{2}]/,"23") <= grabs "x" s grabs two digits each combination. is there easier way i'm not understanding? a.gsub(/\d{4} \d{4} \d{4} xxx\kxx/, '23') \d{4} = 4 digits what \k drop matched far. can use don't replace entire number, still able validate have in desired format.
Read more

jquery - Clone last and append item to closest class -

-
this bare-bones code on page: <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <di...
Read more

css - Can I use the :after pseudo-element on an input field? -

-
i trying use :after css pseudo-element on input field, not work. if use span , works ok. <style type="text/css"> .mystyle:after {content:url(smiley.gif);} .mystyle {color:red;} </style> this works (puts smiley after "buu!" , before "some more") <span class="mystyle">buuu!</span>a more this not work - colors somevalue in red, there no smiley. <input class="mystyle" type="text" value="somevalue"> what doing wrong? should use pseudo-selector? note: cannot add span around input , because being generated third-party control. :after , :before not supported in internet explorer 7 , under, on elements. it's not meant used on replaced elements such form elements (inputs) , image elements . in other words it's impossible pure css. however if using jquery can use $(".mystyle").after("add smiley here"); api docs on .after to ...
Read more