php making query from mysql database getting error like Unknown column in 'where clause' -

-

i have piece of code in php make query mysql database

if(isset($_session["esb2b_userid"])){      $check_row = mysql_num_rows(mysql_query("select * esb2b_basket es_session='.$site.' , es_uid=".$_session["esb2b_userid"]) or die(mysql_error()));       echo "logged in <b>" . $_session["esb2b_username"] . "</b>" ;     ?> <?   }else{     ?>  <? echo "$to" ?> our website <? } ?> <? if($_session['esb2b_userid']=='')             {?> <span id="log-info"><a href="<?=$domain_url?>/signup.html"><? echo "$join_free" ?></a><?php }?> |       <? if($_session['esb2b_userid']=='')             {?> <a href="<?=$domain_url?>/signin.php?file="><? echo "$sign_in" ?></a><?php } else { ?><a href="<?=$domain_url?>/logout.php" > <? echo "$sign_out" ?> </a><?php }?>

but here getting error this

unknown column 'esb2b_userid' in 'where clause'

so can kindly tell me whay getting result , how can solve issue? , suggestions appreciable. thanks

change this

mysql_query("select * esb2b_basket es_session='.$site.' , es_uid=".$_session["esb2b_userid"])

to

mysql_query("select * esb2b_basket es_session='".$site."' , es_uid=".$_session["esb2b_userid"])

Comments

Post a Comment

Popular posts from this blog

ruby - Trying to change last to "x"s to 23 -

-
i have been playing around irb , have string looks this: irb(main):072:0> puts ["[\"4354 5432 5432 xxxxx\", \"6547 6547 8543 xxxxx\", \"2344 6543 6674 xxxxx\", \"2346 6236 7543 xxxxx\", \"1273 5585 5587 xxxxx\"]"] => nil irb(main):073:0> what want gsub last 2 "x" s of each 17 digit combination, 23 . what i've tried far (i've been using rubular): a.gsub(/\d[x]/,"23") <= grabs "x" s i'm close a.gsub(/\w[x{2}]/,"23") <= grabs "x" s grabs two digits each combination. is there easier way i'm not understanding? a.gsub(/\d{4} \d{4} \d{4} xxx\kxx/, '23') \d{4} = 4 digits what \k drop matched far. can use don't replace entire number, still able validate have in desired format.
Read more

jquery - Clone last and append item to closest class -

-
this bare-bones code on page: <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <div class="list-container"> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> <div class="single-list-item"> <button>remove</button> </div> </div> <p><button class="add-list-item">add</button></p> <di...
Read more

css - Can I use the :after pseudo-element on an input field? -

-
i trying use :after css pseudo-element on input field, not work. if use span , works ok. <style type="text/css"> .mystyle:after {content:url(smiley.gif);} .mystyle {color:red;} </style> this works (puts smiley after "buu!" , before "some more") <span class="mystyle">buuu!</span>a more this not work - colors somevalue in red, there no smiley. <input class="mystyle" type="text" value="somevalue"> what doing wrong? should use pseudo-selector? note: cannot add span around input , because being generated third-party control. :after , :before not supported in internet explorer 7 , under, on elements. it's not meant used on replaced elements such form elements (inputs) , image elements . in other words it's impossible pure css. however if using jquery can use $(".mystyle").after("add smiley here"); api docs on .after to ...
Read more