ruby - Trying to change last to "x"s to 23 -

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i have been playing around irb , have string looks this:

irb(main):072:0> puts ["[\"4354 5432 5432 xxxxx\", \"6547 6547 8543 xxxxx\", \"2344 6543 6674 xxxxx\", \"2346 6236 7543 xxxxx\", \"1273 5585 5587 xxxxx\"]"] => nil irb(main):073:0>

what want gsub last 2 "x"s of each 17 digit combination, 23.

what i've tried far (i've been using rubular):

  • a.gsub(/\d[x]/,"23") <= grabs "x"s i'm close
  • a.gsub(/\w[x{2}]/,"23") <= grabs "x"s grabs two digits each combination.

is there easier way i'm not understanding?

a.gsub(/\d{4} \d{4} \d{4} xxx\kxx/, '23')

\d{4} = 4 digits

what \k drop matched far. can use don't replace entire number, still able validate have in desired format.


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