java - What does the following program? -

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• is java “pass-by-reference” or “pass-by-value”? 74 answers

    class ideone     {       int x;       public static void main (string[] args) throws java.lang.exception       {          ideone i;          = new ideone();          i.x = 25;          system.out.println(i.x);          f(i);          system.out.println(i.x);          g(i);          system.out.println(i.x);       }        public static void f(ideone j){          j = new ideone();          j.x = 55; // changes new instance of j. not changing actual object       }        public static void j(ideone j){          j.x = 52; // modifies actual object       }   } 

i have doubt in this. in case of j function, modifies actual object. not pass reference? passing object , modifying inside j.

but doing samein function f also. passing object , modifying it. not modifying original object.

i confused behaviour between these.

as per highly voted answer, passing url in both cases. , modifying content in url. visible in 1 case not in other case.

the f method overwrites reference j passed it. therefore cannot change state of ideone instance reference passed caller. note assignment j = new ideone() not affect caller of f, since java passes value of reference variable, not reference it.

the j method doesn't overwrite reference, can modify state of instance referred it.