csv - How to get the actual value of a cell with openpyxl? -

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i'm beginner python , need help. i'm using python 2.7 , i'm trying retrieve cell values of excel file , store csv file. code following:

import os, openpyxl, csv aggname = "deu"  wb_source = openpyxl.load_workbook(filename, data_only = true) app_file = open(filename,'a') dest_file = csv.writer(app_file, delimiter=',', lineterminator='\n')  calib_sheet = wb_source.get_sheet_by_name('calibration') data = calib_sheet['b78:c88'] data = list(data) print(data)  in range(len(data)):     dest_file.writerow(data[i])  app_file.close()

in csv file, this, instead of actual value (for example in case: sfcg, 99103).

<cell calibration.b78>,<cell calibration.c78> <cell calibration.b79>,<cell calibration.c79> <cell calibration.b80>,<cell calibration.c80> <cell calibration.b81>,<cell calibration.c81> <cell calibration.b82>,<cell calibration.c82> <cell calibration.b83>,<cell calibration.c83> <cell calibration.b84>,<cell calibration.c84> <cell calibration.b85>,<cell calibration.c85> <cell calibration.b86>,<cell calibration.c86> <cell calibration.b87>,<cell calibration.c87> <cell calibration.b88>,<cell calibration.c88>

i tried set data_only = true, when opening excel file suggested in answers similar questions doesn't solve problem.

---------------edit-------------

taking account first 2 answers got (thank you!), tried several things:

for in range(len(data)):    dest_file.writerows(data[i].value)

i error message : 

for in range(len(data)):    dest_file.writerows(data[i].values) traceback (most recent call last):    file "<ipython-input-78-27828c989b39>", line 2, in <module>     dest_file.writerows(data[i].values)  attributeerror: 'tuple' object has no attribute 'values'

then tried instead:

for in range(len(data)):     j in range(2):         dest_file.writerow(data[i][j].value)

and have following error message:

for in range(len(data)):     j in range(2):         dest_file.writerow(data[i][j].value)   traceback (most recent call last):    file "<ipython-input-80-c571abd7c3ec>", line 3, in <module>     dest_file.writerow(data[i][j].value)  error: sequence expected

so then, tried this:

import os, openpyxl, csv  wb_source = openpyxl.load_workbook(filename, data_only=true) app_file = open(filename,'a') dest_file = csv.writer(app_file, delimiter=',', lineterminator='\n')   calib_sheet = wb_source.get_sheet_by_name('calibration')  list(calib_sheet.iter_rows('b78:c88'))  row in calib_sheet.iter_rows('b78:c88'):     cell in row:         dest_file.writerow(cell.value)

only error message:

traceback (most recent call last):    file "<ipython-input-81-5bed62b45985>", line 12, in <module>     dest_file.writerow(cell.value)  error: sequence expected

for "sequence expected" error suppose python expects list rather single cell, did this:

import os, openpyxl, csv

wb_source = openpyxl.load_workbook(filename, data_only=true) app_file = open(filename,'a') dest_file = csv.writer(app_file, delimiter=',', lineterminator='\n')   calib_sheet = wb_source.get_sheet_by_name('calibration')  list(calib_sheet.iter_rows('b78:c88'))  row in calib_sheet.iter_rows('b78:c88'):         dest_file.writerow(row)

there no error message reference of cell in csv file , changing dest_file.writerow(row.value) brings me tuple error.

i still need help!

you've forgot cell's value! see the documentation


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