python - Extraction of 2 or more digit number into a list from string like 12+13 -

i'm trying extract numbers string "12+13".

when extract numbers list becomes [1,2,1,3]

actually want list take numbers [12,13] , 12,13 should integers also.

i have tried level best solve this,the following code

but still has disadvantage .

i forced put space @ end of string...for it's correct functioning.

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my code

def extract(string1):     l=len(string1)     pos=0     num=[]     continuity=0     in range(l):          if string[i].isdigit()==true:             continuity+=1          else:              num=num+ [int(string[pos:continuity])]             continuity+=1             pos=continuity     return num  string="1+134-15 "#added spaces @ end of string  num1=[]  num1=extract(string)  print num1 

the other answer great (as of now), want provide detailed explanation. what trying split string on "+" symbol. in python, can done str.split("+").

when translates code, turns out this.

ourstr = "12+13" ourstr = ourstr.split("+") 

but, don't want convert integers? in python, can use list comprehension int() achieve result.

to convert entire array ints, can use. pretty loops on each index, , converts string integer.

str = [int(s) s in ourstr] 

combining together, get

ourstr = "12+13" ourstr = ourstr.split("+") ourstr = [int(s) s in ourstr] 

but lets might other unknown symbols in array. @idos used, idea check make sure number before putting in array.

we can further refine code to:

ourstr = "12+13" ourstr = ourstr.split("+") ourstr = [int(s) s in ourstr if s.isdigit()]