Java regex, delete content to the left of comma -

i got string bunch of numbers separated "," in following form :

1.2223232323232323,74.00 

i want them string [], need number right of comma. (74.00). the list have abouth 10,000 different lines 1 above. right i'm using string.split(",") gives me :

system.out.println(string[1]) = 1.2223232323232323  74.00 

why not split 2 diefferent indexds? thought should on split :

 system.out.println(string[1]) = 1.2223232323232323  system.out.println(string[2]) = 74.00 

but, on string[] array = string.split (",") produces 1 index both values separated newline.

and need 74.00 assume need use regex, kind of greek me. me out :)?

if it's in file:

scanner sc = new scanner(new file("...")); sc.usedelimiter("(\r?\n)?.*?,"); while (sc.hasnext())   system.out.println(sc.next()); 

if it's 1 giant string, separated new-lines:

string onegiantstring = "1.22,74.00\n1.22,74.00\n1.22,74.00"; scanner sc = new scanner(onegiantstring); sc.usedelimiter("(\r?\n)?.*?,"); while (sc.hasnext())   system.out.println(sc.next()); 

if it's single string each:

string line = "1.2223232323232323,74.00"; system.out.println(line.replacefirst(".*?,", "")); 

regex explanation:

(\r?\n)? means optional new-line character.
. means wildcard.
.*? means 0 or more wildcards (*? opposed * means non-greedy matching, doesn't mean you).
, means, well, ..., comma.

reference.

split file or single string:

string line = "1.2223232323232323,74.00"; string value = line.split(",")[1]; 

split 1 giant string (also needs regex) (but i'd prefer scanner, doesn't need memory):

string line = "1.22,74.00\n1.22,74.00\n1.22,74.00"; string[] array = line.split("(\r?\n)?.*?,"); (int = 1; < array.length; i++) // first element empty    system.out.println(array[i]);